{"author_name":"csanyk","cat":"LD - Misc","comments":[{"author_name":"","time":"December 20, 2012 11:13 am","epoch":1356019980,"text":"Yeah, that is a very confusing subtraction <img src=\"http:\/\/ludumdare.com\/compo\/wp-includes\/images\/smilies\/simple-smile.png\" alt=\":)\" class=\"wp-smiley\" style=\"height: 1em; max-height: 1em;\" \/><br \/>\n Whatever they use for kind of formula, it seems to do a good job of making games visible that &#8220;deserve it&#8221; (high coolness relative to ratings).","spam":"N"},{"author_name":"","time":"December 20, 2012 11:16 am","epoch":1356020160,"text":"It has something to do with how many ratings you have. If someone has R5 C5, their game has more visibility than someone with R40 C40. The 47 is just some kind of a base number that rises with the ratings.","spam":"N"},{"author_name":"AnnaGavaldaKedavra","time":"December 20, 2012 11:21 am","epoch":1356020460,"text":"It means that visibility is based on the ratings you make and the ratings you get, the actual formula is more criptic than R-C= D and we don&#8217;t need to have it.","spam":"N"},{"author_name":"Patacorow","time":"December 20, 2012 11:23 am","epoch":1356020580,"text":"No! Stop talking about D! It will create a black hole!!<br \/>\n Some things just can&#8217;t be tampered with!!!!","spam":"N"},{"author_name":"sorceress","time":"December 20, 2012 12:21 pm","epoch":1356024060,"text":"D = 50 + R &#8211; 5*sqrt(C&#8217;)","spam":"N"},{"author_name":"","time":"December 20, 2012 12:36 pm","epoch":1356024960,"text":"That is a very good formula for getting everyone involved. It is also great that you can&#8217;t really tamper with it beyond 100 ratings.<br \/>\n I have never seen any use of L though. The &#8220;looser&#8221; part of the equation, if it is even in there <img src=\"http:\/\/ludumdare.com\/compo\/wp-includes\/images\/smilies\/simple-smile.png\" alt=\":)\" class=\"wp-smiley\" style=\"height: 1em; max-height: 1em;\" \/>","spam":"N"},{"author_name":"mrhill","time":"May 1, 2014 9:02 am","epoch":1398952920,"text":"I think the math is more like (C\/(C+R))*100, that is the procentage of games you rated. so if you rated as many games as you have received review from, that would giva a default of 50 %","spam":"N"}],"epoch":1356018900,"likes":2,"metadata":{"p_key":"47428","p_author":"csanyk","p_authorkey":"10473","p_urlkey":"83092","p_title":"D = Default = R \u2013 C, except not quite that simple","p_cat":"LD - Misc","p_event":"LD25","p_time":"1356018900","p_likes":"2","p_comments":"7","p_status":"UPD5","us_key":"10473","us_name":"csanyk","us_username":"\/author\/csanyk\/","event_start":"1355443200","event_key":"14","event_name":"LD25"},"text":"<p>So for example, my game&#8217;s rating numbers, right now&#8230;<\/p>\n <p>D = 47 =<\/p>\n <p>R = 22<\/p>\n <p>&#8211;<\/p>\n <p>C = 24.<\/p>\n <p>&nbsp;<\/p>\n <p>Except not quite that simple. \u00a0I mean, I guess not. \u00a022-24 = -2, not 47. \u00a0What do these number mean? \u00a0R = Ratings, C = Coolness, what is &#8220;Default&#8221;?<\/p>\n <p>I take this to mean that I&#8217;ve been rated 22 times, and I have rated 24 games. \u00a0But I don&#8217;t get what the &#8220;default&#8221; number 47 is, or how a slightly more complicated subtraction of R &#8211; C somehow equals 47.<\/p>","time":"December 20th, 2012 10:55 am","title":"D = Default = R \u2013 C, except not quite that simple"}